Khan Academy NetWork

Respostas do Khan Academy

当前为 2024-06-18 提交的版本,查看 最新版本

  1. // ==UserScript==
  2. // @name Khan Academy NetWork
  3. // @version 1.0
  4. // @description Respostas do Khan Academy
  5. // @author ArtVital (github@ArtSixn)
  6. // @match https://pt.khanacademy.org/*
  7. // @grant none
  8. // @namespace https://greasyfork.org/users/1319848
  9. // ==/UserScript==
  10.  
  11. let e = JSON.parse;
  12. JSON.parse = function (a, t) {
  13. let n = e(a, t);
  14. try {
  15. if (n && n.data && n.data.assessmentItem && n.data.assessmentItem.item && n.data.assessmentItem.item.itemData) {
  16. n.data.assessmentItem.item.itemData = "{\"answerArea\":{\"calculator\":false,\"chi2Table\":false,\"periodicTable\":false,\"tTable\":false,\"zTable\":false},\"hints\":[{\"content\":\"$\\\\\\\\begin{align}\\\\n\\\\\\\\left(\\\\\\\\dfrac{z^{4}}{6^{2}}\\\\\\\\right)^{-3}&=\\\\\\\\dfrac{\\\\\\\\left(z^{4}\\\\\\\\right)^{-3}}{\\\\\\\\left(6^{2}\\\\\\\\right)^{-3}}\\\\n\\\\\\\\end{align}$\",\"images\":{},\"replace\":false,\"widgets\":{}},{\"content\":\"$\\\\\\\\begin{align}\\\\n\\\\\\\\phantom{\\\\\\\\left(\\\\\\\\dfrac{z^{4}}{6^{2}}\\\\\\\\right)^{-3}}&=\\\\\\\\dfrac{z^{(4)(-3)}}{6^{(2)(-3)}}\\\\n\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n&=\\\\\\\\dfrac{z^{-12}}{6^{-6}}\\\\n\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\n&=\\\\\\\\dfrac{6^{6}}{z^{12}}\\\\n\\\\\\\\end{align}$\",\"images\":{},\"replace\":false,\"widgets\":{}}],\"itemDataVersion\":{\"major\":0,\"minor\":1},\"question\":{\"content\":\"Khan Academy NetWork, @by ArtVital[[☃ radio 1]]\",\"images\":{},\"widgets\":{\"radio 1\":{\"alignment\":\"default\",\"graded\":true,\"options\":{\"choices\":[{\"content\":\"Resposta\",\"correct\":true},{\"content\":\"💀\",\"correct\":false}],\"deselectEnabled\":false,\"displayCount\":null,\"hasNoneOfTheAbove\":false,\"multipleSelect\":false,\"onePerLine\":true,\"randomize\":false},\"static\":false,\"type\":\"radio\",\"version\":{\"major\":1,\"minor\":0}}}}}";
  17. }
  18. } catch (r) {
  19. console.error("Erro module:", r);
  20. }
  21. return n;
  22. };